About 4,470,000 results
Open links in new tab
  1. 海运中DEM与DET分别代表什么?所谓的免堆与免用?所谓场内场外分 …

    Aug 6, 2024 · 海运中,DEM和DET是两种常见的费用术语。DEM代表滞期费(Demurrage Charges),当船舶在港口停留超过预定时间,未能及时卸货或装货,船东会向租船人收取这部分费 …

  2. How do I prove that $\det A= \det A^T$? - Mathematics Stack Exchange

    10 I believe your proof is correct. Note that the best way of proving that $\det (A)=\det (A^t)$ depends very much on the definition of the determinant you are using. My personal favorite way of proving it is …

  3. linear algebra - Why is $\det⁡ (-A)= (-1)^n\det (A)$? - Mathematics ...

    Typically we define determinants by a series of rules from which $\det (\alpha A)=\alpha^n\det (A)$ follows almost immediately. Even defining determinants as the expression used in Andrea's answer …

  4. linear algebra - how does $\det ( (\det A) I)= (\det A)^n ...

    Apr 14, 2014 · $det (A)I$ is a diagonal matrix with all entries equal to $det (A)$. The determinant of a diagonal matrix can be found by multiplying the diagonal entries. So, we get the result.

  5. prove that $\det (ABC) = \det (A) \det (B) \det (C)$ [for any $n×n ...

    Feb 7, 2020 · I was thinking about trying to argue because the numbers of a given matrix multiply as scalars, the determinant is the product of them all and because the order of the multiplication of det …

  6. linear algebra - How to prove $\det \left (e^A\right) = e ...

    Sep 6, 2022 · Prove $$\\det \\left( e^A \\right) = e^{\\operatorname{tr}(A)}$$ for all matrices $A \\in \\mathbb{C}^{n \\times n}$.

  7. Why $\det (A^ {-1}) = 1/\det (A)$? - Mathematics Stack Exchange

    Jul 12, 2016 · Why $\det (A^ {-1}) = 1/\det (A)$? Ask Question Asked 9 years, 5 months ago Modified 4 years, 2 months ago

  8. 目的港DET和DEM 与 场内场外免柜租一样吗?_百度知道

    目的港DET和DEM 与 场内场外免柜租一样吗?目的港DET和DEM与场内场外免柜租是不同的,具体区别如下:1、含义不同:DEMURRAGE指集装箱在承运人或其代理人控制下的集装箱超期(逾期)使 …

  9. The determinant of adjugate matrix - Mathematics Stack Exchange

    Jan 17, 2016 · Thus, its determinant will simply be the product of the diagonal entries, $ (\det A)^n$ Also, using the multiplicity of determinant function, we get $\det (A\cdot adjA) = \det A\cdot \det (adjA)$

  10. linear algebra - How to show that $\det (AB) =\det (A) \det (B ...

    Aug 28, 2011 · Once you buy this interpretation of the determinant, $\det (AB)=\det (A)\det (B)$ follows immediately because the whole point of matrix multiplication is that $AB$ corresponds to the …